First, I have to calculate the slope (m),
m= (y2-y1)/(x2-x1) = (0+1)/(9-6) = 1/3
now, point slope form would be: y = 1/3 (x-9)
Point slope form, y-y1 = m(x-x1)
Here, y1 = -1, x1 = 4, m=8
so, it would be: (y+1) = 8(x-4)
The equation of line in point slope form is given by
→ , where a and b are X intercept and Y intercept respectively.
The given equation is , Ax + B y -C=0 and we have to write it in point slope form, when x=0. and y=0 is
→ Not defined + Not defined=1 or x+y=∞ which is not possible.
Or, when x=0,and y=0,
L.H.S= A×0 +B×0=0
R.H.S=C if C≠0 ,which is a real number.
If C=0, then→ x+y=0, which is slope intercept form when A=B=C=0.
L.H.S ≠ R.H.S
So, there is no line or no line can be written in slope intercept form when ,y=0 and x=0.
f(x) = y
f(-3) = -5